144=s^2+10s

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Solution for 144=s^2+10s equation:



144=s^2+10s
We move all terms to the left:
144-(s^2+10s)=0
We get rid of parentheses
-s^2-10s+144=0
We add all the numbers together, and all the variables
-1s^2-10s+144=0
a = -1; b = -10; c = +144;
Δ = b2-4ac
Δ = -102-4·(-1)·144
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*-1}=\frac{-16}{-2} =+8 $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*-1}=\frac{36}{-2} =-18 $

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